It does so by iterating over every second digit in the card number, starting from the leftmost position, and adding each digit to oddDigitSum.SumOfOddPlace(number) computes the sum of the digits in the odd positions of a card number. The resulting numbers are then passed to getDigit() to get the sum of their digits, which are added to evenDigitSum. It does so by iterating over every second digit in the card number, starting from the second-to-last digit (i.e., the second-to-rightmost position), and multiplying each digit by 2. SumOfDoubleEvenPlace(number) computes the sum of the digits in the even positions of a card number, after doubling each digit. If the number has only one digit, it simply returns that digit as an integer. ![]() If the number has more than one digit, it iterates over each digit in the number and adds them up, returning the resulting sum. GetDigit(number) computes the sum of the digits in a given number. These functions provide a basic implementation of the Luhn algorithm for validating credit and debit card numbers, by computing the sums of the digits in the odd and even positions of the number, and checking whether their sum is divisible by 10.ĭef getDigit ( number ): if len ( number ) > 1 : digitSum = 0 for digit in number : digitSum = int ( digit ) return digitSum return int ( number ) def sumOfDoubleEvenPlace ( number ): evenDigitSum = 0 for i in range ( 1, len ( number ), 2 ): evenDigitSum = getDigit ( str ( int ( number ) * 2 )) return evenDigitSum def sumOfOddPlace ( number ): oddDigitSum = 0 for i in range ( 0, len ( number ), 2 ): oddDigitSum = int ( number ) return oddDigitSum If the result from Step 4 is divisible by 10, the card number is valid otherwise, it is invalid. Now add all single-digit numbers from Step 1 4 4 8 2 3 1 7 8 = 37Īdd all digits in the odd places from right to left in the card number 6 6 0 8 0 7 8 3 = 38 To validate a card number using the Luhn algorithm,ĭouble every second digit from right to left, if doubling a digit results in a two-digit number, we add the two digits together to get a single digit (for illustration, consider the card number 4388576018402626): It works by performing a series of mathematical operations on the digits of the card number. It is also known as the mod 10 algorithm, is a checksum formula used to validate identification numbers, including credit and debit card numbers. > next(v for k, v in ems() if re.In this blog post, we’ll be exploring how to validate credit and debit card numbers using Python.īy the end of this post, you’ll have a solid understanding of how the Luhn algorithm works and how to use it in Python to check whether a given card number is valid or not. number_str = input("Credit Card Number: ") # already str in Python 3 Use the different if blocks just to determine the vendor and store it in a variable, and then do the checking and printing afterwards. You are having a lot of code duplication in the second part, for all the different card vendors. Print("Sorry, but this is not a Credit Card Number !") Print("This is not a Valid \" American Express \" Credit Card") Print("This is a Valid \" American Express \" Credit Card") Print("This is not a Valid \" JCB \" Credit Card") Print("This is a Valid \" JCB \" Credit Card") Print("This is not a Valid \" Discover \" Credit Card") Print("This is a Valid \" Discover \" Credit Card") Print("This is not a Valid \" Diners Club \" Credit Card") Print("This is a Valid \" Diners Club \" Credit Card") If CheckNumberStr = 3 and CheckNumberStr = 6 or CheckNumberStr = 3 and CheckNumberStr = 8 : Print("This is not a Valid \" MasterCard \" Credit Card") Print("This is a Valid \" MasterCard \" Credit Card") WorkingListStr = list(map(str, WorkingList)) Print("\nYour Credit Card Number is : ", CreditCardNumber, "\n")ĬreditCardNumber = list(map(int, CreditCardNumber)) How can I make my code cleaner? #!/usr/bin/python Some of the advanced programmers told me my whole code is messy. I wrote a Python code that is validating Credit Card Numbers.
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